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From: allbery@ncoast.UUCP (Brandon Allbery)
Newsgroups: net.lang.c,net.micro.pc,net.unix
Subject: allocating arrays
Message-ID: <1181@ncoast.UUCP>
Date: Wed, 7-May-86 18:21:12 EDT
Article-I.D.: ncoast.1181
Posted: Wed May  7 18:21:12 1986
Date-Received: Fri, 9-May-86 10:44:56 EDT
References: <200@pyuxv.UUCP>
Reply-To: allbery@ncoast.UUCP (Brandon Allbery)
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Organization: North Coast Computer Resources
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Xref: watmath net.lang.c:8899 net.micro.pc:8106 net.unix:7806

Expires:

Quoted from <200@pyuxv.UUCP> ["Microsoft 'C' - Strange behaviour with doubles"], by cim2@pyuxv.UUCP (Robert L. Fair)...
+---------------
| Consider an array of 15 pointers to arrays of doubles:
| 
| 	double (*parray[15])[];
| 
| The following code to 'malloc' the actual double array barfs on Microsoft 'C',
| with a 'different levels of indirection' warning on the '='.
| The code passes through LINT, and compiles OK on UN*X 5.2
| 
| 	char	*malloc();
| 
| 	parray[0] = (double*)malloc((unsigned)sizeof(double)*75);
| 
| Microsoft produces the same error if the coercion is (double**), (double),
| or nothing at all !
| 
| Any ideas ?
+---------------

double (*parray[15])[]; means:

	an indefinitely-sized array of (or a pointer to)
		an array of 15
			(double *)

You want to allocate an array[15] of (double *)?  ``double *parray[15];''
                  ...an array of 15 (double)?  ``double parray[15][];''

My compiler (pcc) won't even TAKE ``double (*parray[15])[];'' unless it's
initialized or external; apparently sys5 converts it to the declaration
``double *(*parray[15]);'' -- ptr to array[15] of (double *) -- automatically.

--Brandon
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