Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/17/84; site hplabsb.UUCP Path: utzoo!watmath!clyde!burl!ulysses!bellcore!decvax!hplabs!hplabsb!bl From: bl@hplabsb.UUCP (Bruce T. Lowerre) Newsgroups: net.sci Subject: Re: How will it fall? Message-ID: <3461@hplabsb.UUCP> Date: Mon, 5-May-86 14:05:33 EDT Article-I.D.: hplabsb.3461 Posted: Mon May 5 14:05:33 1986 Date-Received: Wed, 7-May-86 01:39:43 EDT References: <632@tekigm2.UUCP> Organization: Hewlett Packard Labs, Palo Alto CA Lines: 17 > Hello Out There, > > Here's a little thought problem that might stir things up a bit. > > Picture yourself on a space station similar to the one used in 2001 > (i.e. a spinning ring or toroid). You are standing in the middle of > one of the decks near the outside edge of the ring and the spin of > the station is providing a "gravity" about equal to that found on > the surface of the Earth. > > If you were to drop a ball (a simple release with no additional > forces applied), would it fall straight down (along a line through > the center of the ring and the point of release) or would it follow > another path (relative to the aforementioned line)? Due to angular momentum (or lack there of) it will fall in a curved path toward the opposite direction of the rotation of the toroid.