Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: utzoo!linus!philabs!prls!pyramid!hplabs!hplabsb!bl From: bl@hplabsb.UUCP (Bruce T. Lowerre) Newsgroups: net.politics,net.sci Subject: Re: Plutonium, Water, Tactical vs. Strategic Message-ID: <3498@hplabsb.UUCP> Date: Fri, 23-May-86 19:28:26 EDT Article-I.D.: hplabsb.3498 Posted: Fri May 23 19:28:26 1986 Date-Received: Sun, 25-May-86 15:40:37 EDT References: <358@drutx.UUCP> <1063@whuxl.UUCP> <2384@jhunix.UUCP> <708@whuts.UUCP> <260@anasazi.UUCP> <163@njitcccc.UUCP> Organization: Hewlett Packard Labs, Palo Alto CA Lines: 12 Xref: linus net.politics:15499 net.sci:605 > > ... > > go down with the CUBE root of radius, not the Square root. Thus a 20 Mt > > bomb (about as big as anyone bothers to build) would wipe out an area > > with only 10 times the radius of the Hiroshima bomb. > Pretty good estimate. I've got one of those handy dandy calculators. > Assuming a 20 megaton bomb detonated at optimum burst height, with > peak pressure to destroy buildings (not hardened) set at 50 psi, > the destruction radius will be 2.6 miles. All very true. However, 50 psi overpressure is overkill! An overpressure of just 5 psi is enough to cause distruction and damage to non-reinforced buildings. At 5 psi, the radius of destruction is 12 miles.