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From: latham@bsdpkh.UUCP
Newsgroups: net.lang.c
Subject: Re: pointers to functions
Message-ID: <214@bsdpkh.UUCP>
Date: Tue, 24-Jun-86 03:11:07 EDT
Article-I.D.: bsdpkh.214
Posted: Tue Jun 24 03:11:07 1986
Date-Received: Wed, 25-Jun-86 07:36:37 EDT
References: <237@killer.UUCP>
Reply-To: latham@bsdpkh.UUCP (Ken Latham)
Organization: AT&T-IS (SDSS), Orlando Fl.
Lines: 51
Keywords: can you cast them?

In article <237@killer.UUCP> toma@killer.UUCP (Tom Armistead) writes:
>The delima - Is it possible to cast a 'pointer to' a function?
>
>What I have is a char * that holds the address of a function.
>int	foo();
>char	*addr = foo;
>Would it be possible to call the function foo() via the variable addr?
>
>Secondly is it possible to have an array of type 'pointer to' function.
>i.e. 
>int  (*function)()[SIZE];
>something like the above, I was able to achieve this using this:
... etc
>Thanx in advance for **ANY** help,
>
>Tom Armistead

FIRST, char *addr = foo;  is a BAAADDDD idea! and NO you can't call foo with it
   ( well you can but .... )

Try, 
	int (* addr)() = foo;

or in general :

	int (* funcptr)();

SECOND an array of such pointers is declared :

	int (* funcptr[])();

	(* funcptr[])  being an array of pointers;
	(* funcptr[])()  ... to functions;
	int (* funcptr[])(); returning an integer;

A BETTER IDEA is to declare 'funcptr' as a type

	typedef int (* funcptr)();

then use it ...

	funcptr foo[1028];

This is much clearer.

incidentally,    ( (int *())addr)();  would do it     (I think?)


			Ken Latham, AT&T-IS (via AGS Inc.), Orlando , FL

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