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From: nz@wucs.UUCP (Neal Ziring)
Newsgroups: net.lang.c
Subject: Re: pointers to functions
Message-ID: <1688@wucs.UUCP>
Date: Wed, 25-Jun-86 22:06:53 EDT
Article-I.D.: wucs.1688
Posted: Wed Jun 25 22:06:53 1986
Date-Received: Sat, 28-Jun-86 04:29:47 EDT
References: <237@killer.UUCP>
Reply-To: nz@wucs.UUCP (Neal Ziring)
Organization: Washington U. Engineering Computer Lab
Lines: 43
Keywords: can you cast them?

In article <237@killer.UUCP> toma@killer.UUCP (Tom Armistead) writes:
 > The delima - Is it possible to cast a 'pointer to' a function?
 > What I have is a char * that holds the address of a function.
 > int	foo();
 > char	*addr = foo;
 > Would it be possible to call the function foo() via the variable addr?

Not sure about this, but I think    
				  i = ( int (*)())addr(arg1,arg2,arg3);
will work.

 > Secondly is it possible to have an array of type 'pointer to' function.
 > i.e. 
 > int  (*function)()[SIZE];
 > something like the above, I was able to achieve this using this:
 > struct	fct {
 >             int  (*func)();
 >             } f_array[SIZE];
 > Is there another way???

Yes, you can declare the array directly, and even initialize it.

int do_err();
int do1();
int do2();

int (*f_array[])() = { do_err, do1, do2 };


 > Thanx in advance for **ANY** help,
 > - Tom

Get cdecl!  That is the program I used to get the declarations above.
It is a neat program that translates between ~English and C declarations.

-- 
...nz (Neal Ziring at WU ECL  -  we're here to provide superior computing.)

	{seismo,ihnp4,cbosgd}!wucs!nz   OR   nz@wucs.UUCP

    "You could get an infinite number of wires into this !*$$#!?! junction 
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				--   Employee of London Electricity Board, 1959