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From: jso@edison.UUCP (John Owens)
Newsgroups: net.lang.c,net.micro.pc,net.unix
Subject: Re: C'mon, guys! (Really, pointer pedagogy)
Message-ID: <811@edison.UUCP>
Date: Thu, 26-Jun-86 14:46:36 EDT
Article-I.D.: edison.811
Posted: Thu Jun 26 14:46:36 1986
Date-Received: Fri, 4-Jul-86 03:41:21 EDT
References: <bu-cs.811> <487@cubsvax.UUCP>
Organization: General Electric Company, Charlottesville, VA
Lines: 33
Xref: watmath net.lang.c:9711 net.micro.pc:8974 net.unix:8501

In article <487@cubsvax.UUCP>, peters@cubsvax.UUCP writes:
> Just a quick remark.  When I was learning C, I understood that "*pi"
> meant "the contents of pi," but somehow had difficulty conceptualizing
> why the declaration "int *pi;" declares pi as a pointer to an int;
> that is, I knew it was a convention I had to memorize, but it didn't
> seem mnemonic to me.  Then, about a month ago, revelation!: read this
> as "the contents of pi is an integer;" which implies, "pi is that
> which contains (or points to)" an integer.
> Peter S. Shenkin	 Columbia Univ. Biology Dept., NY, NY  10027

Maybe it's my machine-language heritage showing, but I've always found
it least confusing to think of "pi" as "the contents of pi" (which is
a pointer), "*pi" as "that which (the contents of) pi points to",
"int i" as declaring i to contain an int, and "int *pi" as declaring
pi to contain a pointer to an int.

The crucial difference is in the notions of "to contain" and "to be".
The trick is that "int i" does not mean that i *is* an int, but that i
*is* a variable which contains an int.  The expression "i" is, of
course, an int: the int which i contains.

As far as the syntax of the declaration goes, this has proven useful:

	int  pi;	(the expression)   pi    is an int
	int *pi;	(the expression)  *pi    is an int
	int  pi[2];	(the expression)   pi[i] is an int
	int *pi();	(the expression)  *pi()  is an int

	John Owens @ General Electric Company	(+1 804 978 5726)
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