Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP
Path: utzoo!mnetor!seismo!caip!clyde!cbatt!ihnp4!ihlpl!psfales
From: psfales@ihlpl.UUCP (Peter Fales)
Newsgroups: net.sources
Subject: Re: FSLS - List big files in file system - (nf)
Message-ID: <1273@ihlpl.UUCP>
Date: Sat, 6-Sep-86 18:17:21 EDT
Article-I.D.: ihlpl.1273
Posted: Sat Sep  6 18:17:21 1986
Date-Received: Sun, 7-Sep-86 05:08:04 EDT
References: <14600002@siedap.UUCP>
Organization: AT&T Bell Laboratories
Lines: 25

> 
> THIS PROGRAM FINDS LARGE FILES IN A GIVEN (BSD) FILE SYSTEM
> ===========================================================
> 
> None of the standard programs (ls, find, du, quot) seem to  do
> exactly  this,  so  I  wrote  'fsls'  to  do the job. It calls
> 'ncheck(8)' for the given file system, captures the result  in
> a  temporary file, calls stat for each file listed and outputs
> a line in the 'ls -l' format for each file with at  least  the
> given number of blocks allocated. 
> 
> If anyone knows how to do this with standard programs,  please
> tell  me how I could have saved time. If anyone improves fsls,
> please let me have the mods. 
> 

I don't know about BSD, but I use the following command on my 3b2
(System V) for clearing out big files on the disk:

find / -size +nnn -print

Where nnn is the cutoff point in blocks (512 byte blocks).  To better
simulate the fsls command describe above, one could type

find / -size +nnn -exec ls -l {} \;