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From: jec@iuvax.indiana.EDU
Newsgroups: comp.sys.amiga
Subject: Re: argv[n][n] doesn't exist
Message-ID: <118300002@iuvax>
Date: Fri, 5-Dec-86 17:32:00 EST
Article-I.D.: iuvax.118300002
Posted: Fri Dec  5 17:32:00 1986
Date-Received: Sun, 7-Dec-86 20:51:43 EST
References: <816@ulowell.UUCP>
Lines: 39
Nf-ID: #R:ulowell.UUCP:816:iuvax:118300002:000:890
Nf-From: iuvax.indiana.EDU!jec    Dec  5 17:32:00 1986


	That is not quite right, argv is indeed an array of pointers to
strings, but strings can be arrays of characters.  For instance:

------
#include <stdio.h>

main(argc, argv)
int argc;
char *argv[];
{
	char c;
	int i;

	if (argc != 2) {
		fprintf(stderr, "usage: %s <some string>\n", argv[0]);
		exit(1);
	}
	printf("(1) argv[1] == %s\n", argv[1]);
	printf("(2) argv[1] == ");
	for (i=0;;i++) {
		c = argv[1][i];
		if (c == '\0') break;
		putchar(c);
	}
	putchar('\n');
}
-----
	 
	should produce the same results on any intellegent compiler.

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