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From: rlk@chinet.UUCP (Richard Klappal)
Newsgroups: comp.sources.d
Subject: Re: Z80 -> 8080 converter
Message-ID: <1036@chinet.UUCP>
Date: Mon, 19-Jan-87 00:10:47 EST
Article-I.D.: chinet.1036
Posted: Mon Jan 19 00:10:47 1987
Date-Received: Tue, 20-Jan-87 04:13:30 EST
References: <4010003@hpvcla.HP.COM>
Reply-To: rlk@chinet.UUCP (Richard Klappal)
Organization: Chinet - Public Access Unix
Lines: 21


Not withstanding the 250 (+/-) object code combinations of the 8080
and the 796 combos for the Z-80, and (as I understand it) Intel
copyrighted the mnemonics for the 8080, preventing their use
by Zilog,

	The Microsoft M-80 assembler will handle both sets of
	mnemonics, (both in the same program, if desired), or
	check a bulletin board for CP/M to find one of the
	PD Z-80 assemblers (z80asm is one, I believe.) if your
	need doesn't warrant buying one.


I speak for myself only, and have no financial interest in the
success or failure of Microsoft Corp.

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