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From: janm@runx.OZ (Jan Mikkelsen)
Newsgroups: comp.sources.d
Subject: Re: Z80 -> 8080 converter
Message-ID: <605@runx.OZ>
Date: Sat, 17-Jan-87 05:35:53 EST
Article-I.D.: runx.605
Posted: Sat Jan 17 05:35:53 1987
Date-Received: Sat, 24-Jan-87 13:48:01 EST
References: <249@rocksanne.UUCP> <175@herman.UUCP>
Reply-To: janm@runx.OZ (Jan Mikkelsen)
Organization: RUNX  Un*x Timeshare. Sydney, Australia.
Lines: 22

In article <175@herman.UUCP>, det@herman.UUCP (Derek Terveer) writes:

>I believe that z80 has a mere two instructions that 8080 doesn't have.
>Therefore, most likely, your z80 program will run unchanged with the 8080
>assembler (I hope i'm right in this).  (As long as the z80 code doesn't use
>those two instructions that is)

	The Z80 is object compatible with the 8080, but *not* the other way
around! For examply, the Z80 has two 16 bit index registers, which the 8080
does not have, IX and IY. Now if a compiler is going to ignore two 16 bit
registers, it would not be a very good one. I very much double good Z80 code
could run unmodified on an 8080. Maybe a macro assembler, with macros for the
Z80 instructions in 8080 code?

		Jan Mikkelsen.


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I KNOW there is something I have forgotten .... Of cource! The witty remark!