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Path: utzoo!watmath!clyde!ima!johnl
From: johnl@ima.UUCP
Newsgroups: comp.sys.ibm.pc
Subject: Re: Funtion 4BH of interruption 21H
Message-ID: <470@ima.UUCP>
Date: Sat, 31-Jan-87 16:20:15 EST
Article-I.D.: ima.470
Posted: Sat Jan 31 16:20:15 1987
Date-Received: Sat, 31-Jan-87 23:56:15 EST
References: <1379@imag.UUCP>
Reply-To: johnl@ima.UUCP (John R. Levine)
Distribution: world
Organization: Javelin Software Corporation
Lines: 20

In article <1379@imag.UUCP> serge@imag.UUCP (Serge ROUVEYROL de la ROUVETIERE) writes:
>We have got a problem with the function 4BH of interruption 21H (load only)
>
>We don't understand :
>      -if the PSP is created or not ?  [It's not]
>      -if we must allocate the memory ourselves or if the INT 21H do it for us
You allocate it yourself.
>      -How to calculate the start segment ?
>       Is it the segment address obtained by memory allocation?
It does not tell you where the start address is; you'd have to read the .EXE
file yourself.

The "load only" function does just that, it loads the file you specify into
a section of your memory.  It is intended for loading overlays.  I wouldn't use
it -- many versions of DOS 2.X do not implement it correctly and smash the
calling program instead.
-- 
John R. Levine, Javelin Software Corp., Cambridge MA +1 617 494 1400
{ ihnp4 | decvax | cbosgd | harvard | yale }!ima!johnl, Levine@YALE.something
Where is Richard Nixon now that we need him?