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From: burris@ihuxz.UUCP
Newsgroups: comp.sys.atari.st
Subject: Re: sizeof("string")
Message-ID: <2011@ihuxz.ATT.COM>
Date: Wed, 15-Apr-87 08:54:45 EST
Article-I.D.: ihuxz.2011
Posted: Wed Apr 15 08:54:45 1987
Date-Received: Fri, 17-Apr-87 03:25:38 EST
References: <8704120143.AA11235@cory.Berkeley.EDU> <2006@ihuxz.ATT.COM> <1765@trwrb.UUCP>
Organization: AT&T Bell Laboratories - Naperville, Illinois
Lines: 31
Summary: I stand corrected.

In article <1765@trwrb.UUCP>, sansom@trwrb.UUCP (Richard Sansom) writes:
> (This is getting out of hand) - I just ran your program on our 4.2 BSD
> system and came up with the following results:
> 
> 20
> 4
> 6
> 

char	string[ 20 ];
char	*strpt = "hello";

main()
{
	printf( "%d\n", sizeof( string ) );
	printf( "%d\n", sizeof( strpt ) );
	printf( "%d\n", sizeof( "hello" ) );
}

I stand corrected. This is the correct answer, providing that your machine
has a pointer size of 4 bytes. Evidently the compiler allocates the fixed
string as:

char	string[ 6 ];

Sorry for the confusion. If I had the time to actually try the program I posted
I would have seen that the answer was wrong.


Dave Burris
ihnp4!ihuxz!burris