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From: mkhaw@teknowledge-vaxc.ARPA (Michael Khaw)
Newsgroups: comp.unix.wizards
Subject: Re: impossible problem for find(1)?
Message-ID: <12114@teknowledge-vaxc.ARPA>
Date: Fri, 24-Apr-87 11:59:25 EST
Article-I.D.: teknowle.12114
Posted: Fri Apr 24 11:59:25 1987
Date-Received: Sat, 25-Apr-87 19:15:52 EST
References: <2645@phri.UUCP>
Reply-To: mkhaw@teknowledge-vaxc.UUCP (Michael Khaw)
Organization: Teknowledge, Inc., Palo Alto CA
Lines: 19

In article <2645@phri.UUCP> roy@phri.UUCP (Roy Smith) writes:
>
>	A user posed a problem which I can't solve.  She wants to find all
>the files named *refs which are newer than a file called INDEX in the same
>directory.  Thus she wants to know if any of ./x/foorefs, ./x/barrefs or
>./x/bazrefs is newer than ./x/INDEX, and if ./y/z/refs is newer than
>./y/z/INDEX, etc.  I can't think of how to do this with find, or even any

How about (csh)

	% foreach dir (x y)	# `pwd` == parent of x and y
	?	find $dir -name '*refs' -newer $dir/INDEX -print
	? end

Mike Khaw
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