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Path: utzoo!mnetor!seismo!mimsy!chris
From: chris@mimsy.UUCP (Chris Torek)
Newsgroups: comp.unix.wizards
Subject: Re: impossible problem for find(1)?
Message-ID: <6454@mimsy.UUCP>
Date: Fri, 24-Apr-87 21:10:44 EST
Article-I.D.: mimsy.6454
Posted: Fri Apr 24 21:10:44 1987
Date-Received: Sun, 26-Apr-87 00:35:33 EST
References: <2645@phri.UUCP>
Organization: U of Maryland, Dept. of Computer Science, Coll. Pk., MD 20742
Lines: 43

In article <2645@phri.UUCP> roy@phri.UUCP (Roy Smith) writes:
>[problem:] find all the files named *refs which are newer than a
>file called INDEX in the same directory [as the *refs files].

If you have the `newer' program, this is easy: use -exec and a
short script that runs newer on the given file and the equivalent
INDEX file.  Without newer, the most efficient way to tackle this
is, probably, to first list all the `*refs' files with directories:

	find . -name \*refs -print |

Break up the result by directory name:

	awk -F/ '{
		dir = substr($0, 1, length($0) - length($NF));
		if (dir != last) {
			if (any)
				print "/shazam";
			any = 0;
		} else {
			if (any == 0) {
				any = 1;
				print "testthem " dir " << \\/shazam"
			}
			print $NF
		}
	}' | sh

The `testthem' script then looks something like this:

	cd $1
	if [ ! -f INDEX ]; then
		echo "$1: no INDEX file"
		cat		# list them all
		exit 1
	fi
	echo $1
	find `cat` -newer INDEX -print

and of course you can play games with formatting.
-- 
In-Real-Life: Chris Torek, Univ of MD Comp Sci Dept (+1 301 454 7690)
UUCP:	seismo!mimsy!chris	ARPA/CSNet:	chris@mimsy.umd.edu