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From: rmg@mips.UUCP (Richard M. Geiger)
Newsgroups: comp.unix.wizards
Subject: Re: impossible problem for find(1)?
Message-ID: <340@quacky.UUCP>
Date: Fri, 24-Apr-87 19:42:44 EDT
Article-I.D.: quacky.340
Posted: Fri Apr 24 19:42:44 1987
Date-Received: Sun, 26-Apr-87 03:16:11 EDT
References: <2645@phri.UUCP>
Reply-To: rmg@quacky.UUCP (Richard M. Geiger)
Organization: MIPS Computer Systems, Sunnyvale, CA
Lines: 35

In article <2645@phri.UUCP> roy@phri.UUCP (Roy Smith) writes:
>
>	A user posed a problem which I can't solve.  She wants to find all
>the files named *refs which are newer than a file called INDEX in the same
>directory.  Thus she wants to know if any of ./x/foorefs, ./x/barrefs or
>./x/bazrefs is newer than ./x/INDEX, and if ./y/z/refs is newer than
>./y/z/INDEX, etc.  I can't think of how to do this with find, or even any
>combination of find and any other standard tools.  We're running MtXinu
>4.3BSD/NFS on a Vax and Sun-3.1 on some Sun-3's.

Seems like you should be able to skin this cat with something like this...

a script, /user/rmg/bin/sinceindex:

  #!/bin/sh
  echo ===== "$1" =====
  cd "$1"
  ls -t *refs INDEX 2>/dev/null | sed -n -e '/^INDEX$/
  p'

and a find command:

  find . -type d -exec /user/rmg/bin/sinceindex {} \;

This seems to work. 

I fiddled for a bit with getting it all on one command line, (to keep from
having to have the script), but ran out of patience. I expect it could be
done without the script.

-- 
- Rich Geiger
{decvax,ucbvax,ihnp4}!decwrl!mips!rmg
MIPS Computer Systems, 930 E. Arques, Sunnyvale, CA 94086
(408) 720-1700 x308 [Day Job]  (408) 739-7911 [home]