Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: utzoo!mnetor!seismo!ut-sally!husc6!cca!mirror!prism!billc From: billc@prism.UUCP Newsgroups: sci.crypt Subject: Re: Spacing of Prime Numbers Message-ID: <201000001@prism> Date: Mon, 1-Jun-87 13:46:00 EDT Article-I.D.: prism.201000001 Posted: Mon Jun 1 13:46:00 1987 Date-Received: Tue, 9-Jun-87 07:09:04 EDT References: <28047@rochester.ARPA> Lines: 34 Nf-ID: #R:rochester.ARPA:-2804700:prism:201000001:000:1493 Nf-From: prism.UUCP!billc Jun 1 13:46:00 1987 ==/* Written 2:39 am May 24, 1987 by falk@sun.UUCP in prism:sci.crypt */ ==In article <1938@husc6.UUCP>, greg@endor.harvard.edu (Greg) writes: ==> > Prove there is a sequence of at least one million ==> > consecutive integers, none of whom are prime. ==> ==> 1000001! + n is divisible by n for 2<=n<=1000001. == ==I'm confused. How does this prove that there's a million consecutive ==composite numbers? All I see is that there's a composite number with ==a million consecutive factors. == ==-- == -ed falk, sun microsystems, falk@sun.com ==terrorist, cryptography, DES, drugs, cipher, secret, decode, NSA, CIA, NRO. 1000001! is indeed a number with a million consecutive factors. So how does this help us, you ask? The point is that for any number between one and one million, call it n, 1000001! can be written as c*n, where c is 1000001!/n. Thus, 1000001! + n can be written as (c+1) * n. That means that 1000001! + n is not a prime. Now that's for any of a million consecutive n's! Thus we've created a string of one million composites. This method can be used to prove that for any number n, a string of consecutive composites can be found. (This is the principle of mathematical induction. See a good reference like Calculus Vol. I by Tom Apostol.) ---- Bill Callahan billc@mirror.TMC.COM {mit-eddie, ihnp4, wjh12, cca, cbosgd, seismo}!mirror!billc Mirror Systems 2067 Massachusetts Avenue, Cambridge, MA 02140 Telephone: 617-661-0777