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From: ark@alice.UUCP
Newsgroups: comp.lang.c++
Subject: Re: Functions as arguments ("cfront" bug?)
Message-ID: <7181@alice.UUCP>
Date: Sat, 15-Aug-87 17:11:38 EDT
Article-I.D.: alice.7181
Posted: Sat Aug 15 17:11:38 1987
Date-Received: Sun, 16-Aug-87 11:59:33 EDT
References: <297@pvab.UUCP> <25710@sun.uucp>
Organization: AT&T Bell Laboratories, Liberty Corner NJ
Lines: 64

In article <25710@sun.uucp>, guy@gorodish.UUCP writes:
> 1	#include <stdio.h>
> 2
> 3	static int
> 4	func1(int x)
> 5	{
> 6		return x + 1;
> 7	}
> 8
> 9	static int
> 10	func2(int (*funcp)(int x))
> 11	{
> 12		return (*funcp)(33);
> 13	}
> 14
> 15	int
> 16	main(int argc, char **argv)
> 17	{
> 18		(void) printf("%d\n", func2(func1));
> 19	}
> 
> with C++ 1.1 and "cfront" got very upset, giving no less than 3 syntax errors
> on line 10, one on line 11, three on line 12, and 1 on line 13.

Yep, it's a bug all right.  Two ways around it.  First, change

	static int func2(int (*funcp)(int x))

to

	static int func2(auto int (*funcp)(int x))

Second possibility is to define a type:

	#include <stdio.h>

	static int
	func1(int x)
	{
		return x + 1;
	}

	typedef int (*FUNCPTYPE) (int);

	static int
	func2(FUNCPTYPE funcp)
	{
		return (*funcp)(33);
	}

	int
	main(int argc, char **argv)
	{
		(void) printf("%d\n", func2(func1));
	}

In both cases, you will get warnings that argc and argv
aren't used.  If you don't use them, you needn't metion them:

	int
	main(int, char **)
	{
		(void) printf("%d\n", func2(func1));
	}