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From: STEINBERGER@SRI.COM (Richard Steinberger)
Newsgroups: comp.os.vms
Subject: C question
Message-ID: <12323814505.10.STEINBERGER@SRI.Com>
Date: Tue, 4-Aug-87 10:54:57 EDT
Article-I.D.: SRI.12323814505.10.STEINBERGER
Posted: Tue Aug  4 10:54:57 1987
Date-Received: Thu, 6-Aug-87 02:21:33 EDT
Sender: daemon@ucbvax.BERKELEY.EDU
Distribution: world
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I'm a fairly new C language user and I apologize in advance if this question
has an obvious answer.  It concerns the use of CALLOC, the memory allocating
function.

On page 9-3 of the VAX C Run Time Reference Library the syntax is described
as:
	#include stdlib
	void *calloc(size_t number, size_t size);

My understanding of ANSI C is that a new use for the VOID keyword is that it
can refer to a function that can return a pointer to any data type and thus
obviate the need for casting.  I tried using the CALLOC function (with
the #include stdlib, which the compiler couldn't find).  The compiler
wouldn't accept this form, declaring something about void refering to
functions that return no arguments (a more "standard" usage for void).
I looked on page D-5 of the same manual where it describes the syntax as:

	char *calloc(unsigned number, unsigned size);

I was able to get this to work when I declare and use them as follows:

	int number, *integer_ptr;
	char *calloc();
	.
	.
	integer_ptr = (int *) calloc(number, sizeof(int));
	.
	.

My questions are:  Is there an error on page 9-3 (as it conflicts with page 
D-5), or am I just not understanding how to use the CALLOC with the void
keyword?  Where, if anywhere, are the size_t data types defined?
I used:
		#include stdlib
and the compiler was unable to find it.  What's wrong here?  In short, what's
the best way to use the CALLOC function?  Thanks to all who reply.

-Ric Steinberger
steinberger@kl.sri.com

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