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From: franco@MIKEY.BBN.COM (Frank A. Lonigro)
Newsgroups: comp.unix.wizards
Subject: addendum to scanf quiz winner!!!
Message-ID: <8547@brl-adm.ARPA>
Date: Wed, 29-Jul-87 11:36:04 EDT
Article-I.D.: brl-adm.8547
Posted: Wed Jul 29 11:36:04 1987
Date-Received: Fri, 31-Jul-87 04:33:41 EDT
Sender: news@brl-adm.ARPA
Lines: 29

I'm afraid I was a little premature in my previous statement that the winner
was actually a loser.  Let me clarify this.

I said that the 'scanf' statement
   scanf("%s %[^#] %*c %[^\n]", s1, s2, s3);
                         ^^^
was a loser because it restricted the fact that a newline could not appear
in the final string except at the end of it.  Well it seem that if you use
this statement to read from the terminal, this is the only way it will work.
What I mean by work is that if one wishes to print out or process the
resulting s1 s2 and s3 strings immediately after reading, this is the format
of the scanf statement one should use.

But on the other hand, if one is not using the 'scanf' to read from the
terminal but is using it to scan a string as in

   char msg[] = "one two three # four \nfive six\n";
   sscanf(msg, "%s %[^#] %*c %[^\n]", s1, s2, s3);

then you won't get the result you want, ie.. include all chars except NULL.

The 'scanf' statement one should use is:
   char msg[] = "one two three # four \nfive six\n";
   sscanf(msg, "%s %[^#] %*c %[\001-\177]", s1, s2, s3);

Sorry for the screw up and for the multiple messages.

thanks for reading,
-franco%mikey.bbn.com@relay.cs.net