Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: utzoo!mnetor!uunet!seismo!rutgers!ames!ptsfa!ihnp4!homxb!houxm!hropus!jgy From: jgy@hropus.UUCP (John Young) Newsgroups: sci.math,sci.crypt Subject: Re: Encryption of Hoffman coded text Message-ID: <1227@hropus.UUCP> Date: Mon, 10-Aug-87 10:06:31 EDT Article-I.D.: hropus.1227 Posted: Mon Aug 10 10:06:31 1987 Date-Received: Tue, 11-Aug-87 04:28:12 EDT References: <10489@linus.UUCP] <7876@mimsy.UUCP> <10604@linus.UUCP> <3515@cit-vax.Caltech.Edu> Organization: Bell Labs, Holmdel, NJ Lines: 19 Xref: mnetor sci.math:1825 sci.crypt:517 David Palmer writes: > If you are going to encrypt a message by the standard breakable techniques, > (Caesar cypher, Ultra, Purple, NBS DES, whatever technique the NSA is > selling to our allies :-) Is decryption more difficult if you use > Hoffman coding (including Hoffman coding of common combinations such as 'th') > on the plaintext before encypherment? I am assuming that the people doing > the attack know that you are doing Hoffman coding and know what the code is. > . > . > . > It seems to me that Hoffman coding makes the plaintext look more 'random' > and, so, less amenable to statistical attack. Is this so? > My first reaction would be to say "yes it would be less amenable to statistical attack", but then I wondered, if it's known your doing Huffman coding (you say it is) then that algorithm has already done the frequency analysis for the code breaker, and the partial-cypher may now be in a "stricter" form. Comments from experts??? (I'm not either)