Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: utzoo!mnetor!uunet!husc6!mit-eddie!ll-xn!ames!orville.nas.nasa.gov!fouts From: fouts@orville.nas.nasa.gov (Marty Fouts) Newsgroups: comp.arch Subject: Re: Power vs number of circuits Message-ID: <2957@ames.arpa> Date: Thu, 1-Oct-87 17:39:01 EDT Article-I.D.: ames.2957 Posted: Thu Oct 1 17:39:01 1987 Date-Received: Mon, 5-Oct-87 07:36:14 EDT References: <732@obiwan.UUCP> Sender: usenet@ames.arpa Reply-To: fouts@orville.nas.nasa.gov.UUCP (Marty Fouts) Lines: 22 In article <732@obiwan.UUCP> mark@mips.UUCP (Mark G. Johnson) writes: >In article <2934@ames.arpa>, lamaster@pioneer.arpa (Hugh LaMaster) writes > > Current Cray technology is a 250MHz processor. Try clocking > > your 68020 or MIPS machine at that speed and see how long it > > takes to melt. > >In the MIPS CPU case, about 3/4 of its 2W power dissipation (at 60 ns >cycle) is due to switching (power = C*V*V*f). However, assume the worst, >that ALL power consumption is due to switching transients. Then you >just scale by (60ns / 4ns) and find that its power at 250 MHz would >be 30 Watts. Since it's now a Cray-class device, it gets to use a >Cray-sized 50 ton refrigeration unit, so 30 Watts should be no problem :-). > Shouldn't you be taking the increase in volume of circuitry into account? After all, MY Cray 2 has 2 gigabytes of memory in the same cabinetry as 4 CPUs. The total effect that the added part count has on power dissipation through can be estimated by multiplying 30 watts by 120000 (the number of parts in a Cray 2 CPU) and dividing by whatever the number of components in a MIPS CPU case are. Since I don't know this number I'll just divide by 100 and come up with 36 KWatts, which is slightly higher than your estimate.