Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Path: utzoo!mnetor!uunet!husc6!cmcl2!brl-adm!adm!GJWELYCH%SUNRISE.BITNET@wiscvm.wisc.EDU From: GJWELYCH%SUNRISE.BITNET@wiscvm.wisc.EDU Newsgroups: comp.lang.c Subject: array declarations.... Message-ID: <9444@brl-adm.ARPA> Date: Tue, 22-Sep-87 22:39:27 EDT Article-I.D.: brl-adm.9444 Posted: Tue Sep 22 22:39:27 1987 Date-Received: Fri, 25-Sep-87 01:41:00 EDT Sender: news@brl-adm.ARPA Lines: 20 hi all, This may seem to be a simple and stupid question, but I can't find an answer to it. Both the prof. and the class were wondering how you declare a pointer to an array of pointers of type int. What we finally thought of is int *(* x)[5]; but, we aren't sure..... If this is incorrect, could you please tell me the correct answer, and explain what int *(* x)[5]; REALLY means.... Thanks in advance, Greg Welych p.s.: please respond directly to me, and if wanted, I'd be willing to post a summary. BITNET address: GJWELYCH@SUNRISE.BITNET EDU address (if reachable): GJWELYCH@AMAX.NPAC.SYR.EDU or GJWELYCH@CM1.NPAC.SYR.EDU or GJWELYCH@SFX.NPAC.SYR.EDU