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From: grt@twitch.UUCP ( G.R.Tomasevich)
Newsgroups: comp.sys.att
Subject: Shell recursion
Message-ID: <806@twitch.UUCP>
Date: Wed, 21-Oct-87 14:49:53 EDT
Article-I.D.: twitch.806
Posted: Wed Oct 21 14:49:53 1987
Date-Received: Sat, 24-Oct-87 09:34:42 EDT
References: <3269@sol.ARPA> <144800004@tiger.UUCP> <201@Ahab.moby.UUCP>
Sender: news@twitch.UUCP
Organization: AT&T Bell Labs, Holmdel, NJ
Lines: 14
Summary: function using argument is different

Someone asked about escaping from
foo () { foo ; }
Someone else gets "ksh: foo: recursive call"
I tried it and got the same result.  Then I tried

	foo () { echo $1; foo `inc $1` ; }
where 'inc' is essentially
	main(n,a) int n; char **a; { printf("%d\n",atoi(a[1])+); }
It is up to 216 and counting.  A number comes out every 2-3 seconds.
Why is this so high?  I see no real difference from the case which uses
no arguments.
-- 
	George Tomasevich, ihnp4!twitch!grt
	AT&T Bell Laboratories, Holmdel, NJ