Path: utzoo!utgpu!water!watmath!clyde!cbosgd!ihnp4!ihlpg!tainter
From: tainter@ihlpg.ATT.COM (Tainter)
Newsgroups: comp.lang.c
Subject: Re: "logical" xor
Message-ID: <4612@ihlpg.ATT.COM>
Date: 12 Jan 88 23:32:52 GMT
References: <11207@brl-adm.ARPA> <20153@teknowledge-vaxc.ARPA>
Organization: AT&T Bell Laboratories - Naperville, Illinois
Lines: 9

In article <20153@teknowledge-vaxc.ARPA>, mkhaw@teknowledge-vaxc.ARPA (Mike Khaw) writes:
> 1^0 = 1; 0^0 = 0; 1^1 = 0 => logical xor should mean "does not equal",
> for which C has a perfectly good symbol, "!="
> Mike Khaw
No.  Logical xor should mean "not logically equal" for which != does not work.
You would still need to do an equivalent of ((A!=0) != (B!=0)).
Note: (!A ^ !B) and (!A != !B) work fine.

--j.a.tainter