Path: utzoo!utgpu!water!watmath!clyde!cbosgd!ucbvax!amdcad!tim
From: tim@amdcad.AMD.COM (Tim Olson)
Newsgroups: comp.lang.c
Subject: Re: Question about type casting
Message-ID: <19994@amdcad.AMD.COM>
Date: 17 Jan 88 21:22:55 GMT
References: <546@xyzzy.UUCP> <5080012@hpfcdc.HP.COM>
Reply-To: tim@amdcad.UUCP (Tim Olson)
Organization: Advanced Micro Devices
Lines: 30

In article <5080012@hpfcdc.HP.COM> boemker@hpfcdc.HP.COM (Tim Boemker) writes:
| > I believe that Standard C does not allow type casting on the left of the 
| > = sign.
|  
| How about this:
| 
| int i;
| char *c;
| 
| c = (char *) &i;
| 
| * (int *) c = 0;
| 
| Are you saying that Standard C doesn't allow c to be recast in that assignment?

I believe that the previous poster really meant that C doesn't allow
*lvalues* to be cast.  In your example, 'c' is not an lvalue, but '*c'
is.  Therefore, you can write

	* (int *) c = 0;
	
but not

	(int)(*c) = 0;


	-- Tim Olson
	Advanced Micro Devices
	(tim@amdcad.amd.com)