Path: utzoo!mnetor!uunet!seismo!sundc!pitstop!sun!amdcad!ames!nrl-cmf!ukma!gatech!udel!rochester!ur-tut!sunybcs!rutgers!im4u!ut-sally!utah-cs!utah-gr!uplherc!esunix!rushfort
From: rushfort@esunix.UUCP (Kevin Rushforth)
Newsgroups: comp.lang.c
Subject: Re: arrays -> pointers
Message-ID: <656@esunix.UUCP>
Date: 19 Jan 88 17:56:33 GMT
References: <3761@sigi.Colorado.EDU>
Organization: Evans & Sutherland, Salt Lake City, Utah
Lines: 41

in article <3761@sigi.Colorado.EDU>, swarbric@tramp.Colorado.EDU (SWARBRICK FRANCIS JOHN) says:
> 
> Here is a line of code that I got out of a book:
> 
> (*(mn+hsel-1)->func[vsel-1])(hsel,vsel);

Correct, assuming the following typedefs and variables (or some equivalent):

typedef void (*funcp)();
typedef struct
{
    funcp *func;
} mystruct;

mystruct *mn;
int vsel,hsel;

> With it using arrays in both places that would look normal I think it would
> look like this:
> 
> (*ms[hsel-1].func[vsel-1])(hsel,vsel);

Also, correct;

> ANyway, does anyone know how to get it to that it won't use *any* array
> brackets?  I tried stuff like:
> 
> (*(*(mn+hsel-1)->func+vsel-1))(hsel,vsel);

Not quite.  This should be written as:

    (**((mn+hsel-1)->func+vsel-1))(hsel,vsel);

In your example, you try to add (vsel-1) to the pointer (mn+hsel-1)->func
AFTER dereferencing it rather than before.  Hope this helps.
-- 
                Kevin C. Rushforth
                Evans & Sutherland Computer Corporation

UUCP Address:   {ihnp4,ucbvax,decvax,allegra}!decwrl!esunix!rushfort
Alternate:      {bellcore,cbosgd,ulysses}!utah-cs!esunix!rushfort