Path: utzoo!utgpu!water!watmath!clyde!rutgers!im4u!ut-sally!utah-cs!utah-gr!uplherc!sp7040!jsp
From: jsp@sp7040.UUCP (John Peters)
Newsgroups: comp.lang.c
Subject: Re: C Quirk??
Summary: why not try
Keywords: Weird_Behavior()
Message-ID: <285@sp7040.UUCP>
Date: 10 Feb 88 01:02:13 GMT
References: <1653@ssc-vax.UUCP>
Organization: Unisys, Salt Lake City, UT
Lines: 77

In article <1653@ssc-vax.UUCP>, dmg@ssc-vax.UUCP (David Geary) writes:
> 
> I've been wondering about this for a long time.  Maybe someone out there
> can shed some light on the subject...
> 
> #include <stdio.h>
> #include <ctype.h>
> 
> main()
> {
>   char ch;
> 
>   puts("Enter a Character:  ");
> 
>   while( (ch = getchar()) )
>   {
>     if( isupper(ch) )
>       tolower(ch);
> 
>     printf("%c\n", ch);
>     puts("Enter a Character:  ");
>   }
> }
> 
> Here's the output that I get when running the above program:
> 
> Enter a Character:
> a
> A
> Enter a Character:
> 
> 
> Enter a Character:
> 
> 
> The first time, everything is ok.  The next time, however, it seems
> to just blow right by the getchar().
> 

This does indead leave the newline in the buffer.  I no of several ways to
get around the problem.  Probabley the easiest (and it can also save a lot
of other hastles) is:

#include <stdio.h>
#include <ctype.h>

#define EVER (;;)

main()
{
    char	a[5];

    for EVER {
	gets (a);
	printf ("%c\n", toupper (a[0]));
    }
}

This gets ride of certain other evils such as accidentally entering more than
one character.

Also you can use the standard scanf botch to do it.

	scanf ("%c%*c", a);  

This tells the program to skip the next character after reading one.

Since it sounds like you are wanting just one character at a time how about
considering putting the system in raw mode so that when you do the getchar
it comes right back at you.  Why wait an force the user to hit a charrage
return.

					--  John  --

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	DISCLAIMER:  My spelling is my own and boy does the company hate it!