Path: utzoo!mnetor!uunet!husc6!mailrus!nrl-cmf!ames!hao!boulder!murillo
From: murillo@sigi.Colorado.EDU (Rodrigo Murillo)
Newsgroups: comp.sys.ibm.pc
Subject: More on setting DOS errorlevel
Message-ID: <4835@sigi.Colorado.EDU>
Date: 14 Mar 88 21:54:45 GMT
Reply-To: murillo@boulder.Colorado.EDU (Rodrigo Murillo)
Followup-To: comp.sys.ibm.pc
Distribution: na
Organization: University of Colorado, Boulder
Lines: 61


I posted an article asking how to set DOS errorlevel from a C program.
Someone suggested exit(errorlevel). But wait...
 
The following code shows that exit(errorlevel) works.  The problem is
that if errorlevel is set with an exit(5) for example, all if tests for
values <= to 5 are tested as true.  This is some sample output showing the
results of passing 5 parameters to the batch file, which calls ERRLEVEL
which does an exit(5):
 
            F:\>errtest 1 2 3 4 5
            F:\>echo off
 
            exit(5);
            FIVE!
            FOUR!
            THREE!
            TWO!
            ONE!
            ZERO!
 
            F:\>
 
If anybody can tell why this is the way it is I would love to hear it.
Why would (errorlevel 0) test true if the exit is exit(5)??!!
 
==>errlevel.c
 
/* exit(n) with the number of paramters passed to it */
 
main(argc, argv)
int argc;
char *argv[];
 
{
   printf("\nexit(%d);\n",argc-1);
   exit(argc-1);
}
/* end of program */
 
 
==>errtest.bat
echo off
errlevel %1 %2 %3 %4 %5 %6 %7 %8
if errorlevel 8 echo EIGHT!
if errorlevel 7 echo SEVEN!
if errorlevel 6 echo SIX!
if errorlevel 5 echo FIVE!
if errorlevel 4 echo FOUR!
if errorlevel 3 echo THREE!
if errorlevel 2 echo TWO!
if errorlevel 1 echo ONE!
if errorlevel 0 echo ZERO!
 
 

-- 
_______________________________________________________________________________
 Rodrigo Murillo, University of Colorado - Boulder  (303) 761-0410 
 murillo@boulder.colorado.edu | ..{hao|nbires}!boulder!murillo
 ( Machines have less problems.  I'd like to be a machine. -- Andy Worhol )