Path: utzoo!mnetor!uunet!husc6!ncar!gatech!mcnc!decvax!decwrl!pyramid!prls!philabs!micomvax!zap!iros1!mcgill-vision!mouse
From: mouse@mcgill-vision.UUCP (der Mouse)
Newsgroups: comp.lang.c
Subject: Re: Why I use C instead of fortran
Message-ID: <980@mcgill-vision.UUCP>
Date: 9 Mar 88 10:16:16 GMT
References: <11440@brl-adm.ARPA> <3597@sdcc6.ucsd.EDU> <257@tolsun.oulu.fi> <259@tolsun.oulu.fi>
Organization: McGill University, Montreal
Lines: 23

In article <259@tolsun.oulu.fi>, jto@tolsun.oulu.fi (Jarkko Oikarinen) writes:
[Apparently this is someone else (Jouko Holopainen?) again]
> In aticle 4882 Tom Stockfisch writes:
>> In article <4257> Jouko Holopainen writes by courtesy of Jarkko Oikarinen:
>> [I use FORTRAN for nothing but complex arithmetic.]  As soon as C++
>> becomes widely available, I won't use fortran at all.
> Can You write a=b**c/d+e... in C++ with complex operators?

Probably not (I don't think you can change the tokenizing rules to make
** a single operator), but you can certainly write a=b^c/d+e.  (Though
you may need to parenthesize to get ^ to take precedence over /, and it
is arguably bad style to have ^ mean XOR for integers and
exponentiation for complex.)

> If this is the case, how can You redefine division?

There is a syntax for it, which I don't know the details of (I don't
use C++; I know what it can do but not the details of how it does it).

					der Mouse

			uucp: mouse@mcgill-vision.uucp
			arpa: mouse@larry.mcrcim.mcgill.edu