Path: utzoo!mnetor!uunet!husc6!cmcl2!phri!bc-cis!raanan
From: raanan@bc-cis.UUCP (Raanan Herrmann)
Newsgroups: comp.unix.xenix
Subject: shell problem
Message-ID: <1171@bc-cis.UUCP>
Date: 19 Mar 88 15:37:25 GMT
Reply-To: raanan@bc-cis.UUCP (Raanan Herrmann)
Organization: Brooklyn College of CUNY, Brooklyn, NY
Lines: 20


	An application I wrote in shell should accept a unix command 
from a user and execute it. The solustion should be:
	read l
	exec $l

	This does not work when $l contain a commands with parameters
(eg. "ls -l") as the error generated is "command not found", and does
not work when the command contain ";" (eg. "ls -l;who").
 
	My solution was;
	read l
	echo $l>tmp$$
	exec tmp$$
 
	But, I don't like this solution - any better ideas. PLEASE, also
e-mail your answer to me, to ron@jkfmny.uucp
-- 
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Ron Herrmann  (jkfmny!ron, ron@jkfmny.UUCP raanan@bklyncis.BITNET)