Path: utzoo!utgpu!water!watmath!clyde!att-cb!osu-cis!tut.cis.ohio-state.edu!bloom-beacon!mit-eddie!uw-beaver!cornell!rochester!PT.CS.CMU.EDU!K.GP.CS.CMU.EDU!lindsay From: lindsay@K.GP.CS.CMU.EDU (Donald Lindsay) Newsgroups: sci.misc Subject: Re: Plantes & actions (was Re: Omni-Americans) Keywords: tides Message-ID: <1246@PT.CS.CMU.EDU> Date: 29 Mar 88 04:17:59 GMT References: <3021@gryphon.CTS.COM> Sender: netnews@PT.CS.CMU.EDU Organization: Carnegie-Mellon University, CS/RI Lines: 39 In article <3021@gryphon.CTS.COM> edk@gryphon.CTS.COM (Ed Kaulakis) writes (in reply to Mark Hopkins): >BUT the 1/R^2 field of Jupiter influences the path of the Earth; what is >observable by a critter such as you or me on the surface of said Earth is >the somewhat!! weaker 1/R^3 tidal psuedo-force. Does this change your >calculations? If so does it change your conclusions? If not why not? Good point. The tidal forces matter. Actually, a tidal force is just the differential force that results when gravitional forces are not quite equal on the near and far sides of something. So, the tidal force has the same units, and competes on an equal footing with other forces. Tidal force (in nano-g's) across the earth, due to: Venus 0.0 note, Mercury is both smaller and further away Mars 0.0 Jupiter 0.0 note, Saturn is both smaller and further away Moon 224..225 due to elliptical orbit of moon Sun 103 earth's orbit is very near circular Tidal force (in nano-g's) across 2m (a human put lengthwise? outspread arms?), due to: a car 1 assume 1000KG, 3m away. a hill 75 assume 30x30x15m of rock, 30m away mountain 75 assume 2x2x1 km of rock, 2km away earth 630 i.e. the tidal stress from your toes to your nose (if flat on back, ~100 nano-g from spine to sternum) Again, the direct (not tidal) force due the most influential planet: Jupiter 15 to 33 Changes, at most, 18 nano-g per six months. Which is about the tidal stress from top to bottom on a Rubik's Cube. -- Don lindsay@k.gp.cs.cmu.edu CMU Computer Science