Path: utzoo!mnetor!uunet!sdrc!scjones
From: scjones@sdrc.UUCP (Larry Jones)
Newsgroups: comp.lang.c
Subject: Re: Bit Addressable Architectures
Message-ID: <259@sdrc.UUCP>
Date: 14 Apr 88 22:05:21 GMT
References: <11702@brl-adm.ARPA> <243@eagle_snax.UUCP> <2245@geac.UUCP> <7684@brl-smoke.ARPA>
Organization: Structural Dynamics Research Corp., Cincinnati
Lines: 26

In article <7684@brl-smoke.ARPA>, gwyn@brl-smoke.ARPA (Doug Gwyn ) writes:
> In article <8646@eleazar.Dartmouth.EDU> major@eleazar.Dartmouth.EDU (Lou Major) writes:
> >char foo[]="This is a test.";
> >sizeof (foo) == sizeof (char *)
> 
> Since when?
> 
> I know that Gould had a bug in their UTX-32 compiler that made it think
> sizeof"......"==sizeof(char *), but they fixed that and in any case
> it's not the same as your example.  So what gives?
> 
> (I don't think the array name is turned into a pointer just because it's
> surrounded by parentheses.)

If it ain't, the compiler's broke!  The sizeof operator can be applied to a
parenthesized type name or to an expression.  Since "foo" isn't a type name,
the operand of sizeof is an expression.  When an array name appears in an
expression and it's not the operand of & or sizeof (whose operand is the
parenthesized express, remember), it's converted into a pointer to the first
element.

----
Larry Jones                         UUCP: uunet!sdrc!scjones
SDRC                                MAIL: 2000 Eastman Dr., Milford, OH  45150
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