Path: utzoo!mnetor!uunet!mcvax!prlb2!kulcs!dannyb
From: dannyb@kulcs.uucp (Danny Backx)
Newsgroups: comp.unix.questions
Subject: Re: Determining system memory
Message-ID: <108@icarus.kulcs.uucp>
Date: 4 Apr 88 13:42:30 GMT
References: <248@lxn.UUCP>
Reply-To: dannyb@kulcs.UUCP (Danny Backx)
Organization: Katholieke Universiteit Leuven, Dept. Computer Science
Lines: 29

In article <248@lxn.UUCP> chris@lxn.UUCP (Christopher D. Orr) writes:
>I have been trying to find a nice, clean way to determine system
>memory under SYS V 2.2.  I have come up with two solutions to this
>problem.  However, there must be a cleaner/faster way :-).

How about opening /dev/mem and seeking to the end ?
The manual entry for lseek(2) says the return value is the position you got at.
So, if you seek to the end (offset 0 relative to the EOF), the return value
of lseek should be the amount of memory your system has.

I don't know if this works on /dev/mem.  It works on ordinary files.
If your program works, this should, too.

The system call you should issue is :

	long	lseek(), pos ;

	pos = lseek(M, 0L, 2);

Don't forget the declaration of lseek() !!!

	Danny

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