Xref: utzoo sci.physics:3470 sci.electronics:2991 Path: utzoo!attcan!uunet!husc6!bloom-beacon!mit-eddie!ll-xn!ames!pasteur!agate!bosco!greg From: greg@jif.berkeley.edu (Greg) Newsgroups: sci.physics,sci.electronics Subject: Re: capacitors Message-ID: <10227@agate.BERKELEY.EDU> Date: 23 May 88 17:09:42 GMT References: <2992@phoenix.Princeton.EDU> Sender: usenet@agate.BERKELEY.EDU Reply-To: greg@bosco.Berkeley.EDU (Greg) Organization: UC Berkeley Lines: 21 In article <2992@phoenix.Princeton.EDU> tycchow@phoenix.Princeton.EDU (Timothy Yi-chung Chow) writes: >Two capacitors, with capacitances C1 and C2 respectively, carry >charges Q1 and Q2 respectively. Find the total energy stored. >Now connect the positive plates and connect the negative plates. >Show that the total energy stored decreases. Where has the >energy gone? It follows from either Maxwell's equations or consistency arguments in special relativity that any electrical system has both non-zero capacitance and non-zero inductance. If there are no resistors, the system is necessarily a collection of harmonic oscillators. If there is (linear) resistance, the system consists of damped harmonic oscillators. A (linear) DC system is one in which the resistances are large enough that the inductances are insignificant. In the above question, if there is non-zero resistance, the energy is lost to heat. If there is no resistance, the DC approximation fails and the system is a harmonic oscillator. -- Greg