Path: utzoo!attcan!uunet!lll-winken!lll-tis!ames!mailrus!husc6!bloom-beacon!mit-eddie!uw-beaver!uw-june!pardo
From: pardo@june.cs.washington.edu (David Keppel)
Newsgroups: comp.lang.c++
Subject: Re: operator precedence question
Summary: C backwards compatability
Message-ID: <5335@june.cs.washington.edu>
Date: 20 Jul 88 17:57:32 GMT
References: <36592@linus.UUCP>
Reply-To: pardo@cs.washington.edu (David Keppel)
Organization: U of Washington, Computer Science, Seattle
Lines: 13

[ Tried e-mail, but it bounced on 3 different addresses.  *sigh* ]

In article <347@gt-eedsp.UUCP> baud@gteedsp.gatech.edu writes:
>[ ... int i=0, t=s; ...   Why is this not char *t = char* s? ]

Because C++ is backwards compatible with C, and the C declaration
rules require that statement to declare two integers.  Actually, makes
sense.  G++ complains, however, if you write:

    t=s, int i=0;

which is too bad.

  ;-D on  ( top 3 US $ military aid: Israel, Egypt, Turkey )  Pardo