Xref: utzoo comp.lang.c:11399 comp.sys.ibm.pc:17296
Path: utzoo!attcan!uunet!sco!seanf
From: seanf@sco.COM (Sean Fagan)
Newsgroups: comp.lang.c,comp.sys.ibm.pc
Subject: Re: Bug list for Microsoft C
Message-ID: <372@scolex>
Date: 19 Jul 88 01:46:36 GMT
References: <4516@pasteur.Berkeley.Edu>
Organization: The Santa Cruz Operation, Inc.
Lines: 25

In article <4516@pasteur.Berkeley.Edu> iverson@cory.Berkeley.EDU.UUCP (Tim Iverson) writes:
>int i=1, j=33;
>
>main() {
>    printf("%x\n", 1<<33);
>    printf("%x\n", 1>>33);
>    printf("%x\n", i<<j);
>    printf("%x\n", i>>j);
>}
>What results do you get? (This might even be interesting on non 86 machines;
>oh boy, I just checked a non 86, and it failed too.)

Under Xenix '386, I get: 2, 0, 2, 0; using the '286 compiler, I get 0, 0, 2,
0.  So, anybody, what does ANSI say (in plain English)?  I tried reading the
draft to see what it should be, and I couldn't make head nor tail of it...
Somebody said, earlier, that both K&R and ANSI say the results are
implementation defined, but, from what I could stand of the draft, it didn't
seem to say that.

>Mike Stump, Cal State Univ, Northridge Comp Sci Department
>aeusemrs@csuna.csun.edu

----------------
Sean Eric Fagan
seanf@sco