Xref: utzoo comp.lang.c:12363 comp.std.c:347
Path: utzoo!attcan!uunet!husc6!uwvax!rutgers!bellcore!clyde!mcdchg!chinet!att!ucbvax!decwrl!meest!djones
From: djones@meest.UUCP (Dave Jones)
Newsgroups: comp.lang.c,comp.std.c
Subject: Re: Calling functions by address
Message-ID: <758@goofy.meest.UUCP>
Date: 30 Aug 88 23:00:35 GMT
References: <679@mssx.UUCP>
Organization: Megatest Corporation, San Jose, Ca
Lines: 24

From article <679@mssx.UUCP>, by src@mssx.UUCP (Pleschutznig Andreas):
...

> 
> So we thought of doing that job by declaring the addresses of the emulation 
> routines and jumping to the routines by address like this
> 
> 	(*addressarray[code]);
> 
> I know, I know that *does not* work, but maybe there is someone knowing to
> get around.

Nothing to "get around".  There is nothing in your way.  You just left off
the empty parameter list ().  (First language Pascal?)

/* declaration */

int routine1(), routine2(), routineN();

int (*addressarray[])() = { routine1, routine2, routineN }; 

/* calling sequence */

  int return_value = (*addressarray[code])();
#!