Path: utzoo!utgpu!water!watmath!clyde!att!osu-cis!tut.cis.ohio-state.edu!bloom-beacon!gatech!udel!udccvax1!tboutell
From: tboutell@vax1.acs.udel.EDU (Thomas B Boutell)
Newsgroups: comp.dcom.modems
Subject: Re: UUCP g stats
Keywords: Baud Bit Byte Asynchronous Serial Line Speed
Message-ID: <2032@udccvax1.acs.udel.EDU>
Date: 8 Oct 88 17:21:46 GMT
References: <184@arnold.UUCP> <1892@van-bc.UUCP>
Reply-To: tboutell@vax1.acs.udel.EDU (Thomas B Boutell)
Organization: University of Delaware
Lines: 12

>>How are you computing bandwidth utilization?
>>(c * 8) / b
>>where b = baud and c = chars. per second?
>You probably want to multiply by (at least) 10 instead of just 8
>since the 1 start bit and 1 to 2 stop bits count here as well.

This is not true under all circumstances, even with asynchronous modems.
The Telebit Trailblazer and USR HST 9600, to name two, are capable of
eliminating the two stop bits when communicating at their highest speeds;
however, your suggestion of multiplying by ten rather than eight under
most circumstances is correct. (To be specific, when using a 2400 baud-
or- less device, it's definitely correct over an asynchronous link.)