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From: schmidt@blanche.ics.uci.edu (Doug Schmidt)
Newsgroups: comp.lang.c++
Subject: overloading new operator in C++
Message-ID: <774@paris.ics.uci.edu>
Date: 9 Oct 88 05:49:59 GMT
Sender: news@paris.ics.uci.edu
Reply-To: Doug Schmidt <schmidt@blanche.ics.uci.edu>
Organization: University of California, Irvine - Dept of ICS
Lines: 37

Hi,

   Would someone please inform me whether the following code is legal
in C++?  If it is, then is the result defined?  G++ 1.27 performs 20
NOPS for the main for loop.  My basic question is:

``Is is possible to hide the new operator in the same fashion as hiding
  the assignment operator `=' , i.e., making it a compile-time error
  to use new?''

----------------------------------------
#include <stream.h>

class Tree_Node {
public:
   static Tree_Node *Base;

private:

   void * operator new ( long ) {
      return ( Base++ );
   } 

};

main() {
   Tree_Node::Base = new Tree_Node [ 20 ];

   for ( int i = 0; i < 20; i++ ) {
      cout << int ( new Tree_Node ) << "\n";
   }
}
----------------------------------------

thanks for any hints,

   Doug Schmidt