Path: utzoo!utgpu!attcan!uunet!steinmetz!davidsen
From: davidsen@steinmetz.ge.com (William E. Davidsen Jr)
Newsgroups: comp.lang.c
Subject: Re: Declaration puzzler (another old question?)
Message-ID: <12309@steinmetz.ge.com>
Date: 5 Oct 88 14:45:25 GMT
References: <30091@oliveb.olivetti.com>
Reply-To: davidsen@crdos1.UUCP (bill davidsen)
Organization: General Electric CRD, Schenectady, NY
Lines: 18

In article <30091@oliveb.olivetti.com> chase@orc.olivetti.com (David Chase) writes:
| I can't figure out how to declare the type of an array with (say) 10
| elements, each of which is that array type.  That is, I want the
| non-error effect of
| 
| 	typedef foo *(foo[10]);

why not:
	typedef int foo[10];
	typedef foo *bar;

Perhaps that will do what you want to do, if not the way you want. The
token after the 'typedef' must be a type, and it seems that foo doesn't
become a type until after compilation of the typedef.
-- 
	bill davidsen		(wedu@ge-crd.arpa)
  {uunet | philabs}!steinmetz!crdos1!davidsen
"Stupidity, like virtue, is its own reward" -me