Path: utzoo!attcan!uunet!ingr!crossgl
From: crossgl@ingr.UUCP (Gordon Cross)
Newsgroups: comp.lang.c
Subject: Re: A curriosity in the C compiler...
Summary: a = b == c is treated as a = (b == c)
Message-ID: <2775@ingr.UUCP>
Date: 31 Oct 88 17:30:25 GMT
References: <530@uvicctr.UUCP>
Organization: Intergraph Corp. Huntsville, Al
Lines: 16

In article <530@uvicctr.UUCP>, sbanner1@uvicctr.UUCP (S. John Banner) writes:
> 
> /*
> 	This is a quick test of the C compiler, for implied bracketing...
> This will determine if the expression "a = b == c" is parsed
> as "(a = b) == c" (which is correct), or as "a = (b == c)" (which
> is not).
> */

The correct treatment of the expression a = b == c is a = (b == c) and NOT
(a = b) == c!!  Check your info on operator precedence.  I believe that you
will discover that == has higher precedence than =.


Gordon Cross
Intergraph Corp.  Huntsville, AL