Path: utzoo!attcan!uunet!ncrlnk!ncr-sd!hp-sdd!hplabs!hpda!hpcupt1!dvl
From: dvl@hpcupt1.HP.COM (Doug Larson)
Newsgroups: comp.sys.hp
Subject: Re: u.u_comm on HP9000/800
Message-ID: <7410024@hpcupt1.HP.COM>
Date: 8 Nov 88 01:00:21 GMT
References: <17014@santra.UUCP>
Organization: Hewlett Packard, Cupertino
Lines: 23


I assume you are porting from a Berkeley 4.x system.  In these systems
the u area is located at a constant location in the third quadrant.  

In HP-UX on the 800 series, this is not the case.  The u areas are in 
an array in system space.  E.g. proc[i] matches u[i].  The  tricky
part comes about for two reasons; The u areas are not sizeof(struct user)
apart, and of course the particular u area you are interested in may
not be mapped in.

In any case, to find u[i];

#define USIZ (sizeof(struct user))
/* make sure the pid array is double word aligned!! */
#define PIDSIZ ((npids * sizeof(int)+sizeof(double) -1) & ~(sizeof(double) -1))

byte address = ubase + i*(USIZ+PIDSIZ) 		(Make appropriate type casts)

gives you the byte address system virtual space.   Ubase is where the
user areas start.  Good luck!

	Doug Larson
	hplabs!hpda!dvl