Xref: utzoo rec.audio:8787 sci.electronics:4177 sci.math:4705 Path: utzoo!yunexus!geac!syntron!jtsv16!uunet!lll-winken!lll-lcc!lll-tis!helios.ee.lbl.gov!pasteur!agate!bionet!apple!rutgers!att!mtuxo!mtgzz!drutx!tbb From: tbb@drutx.ATT.COM (Tom Barber) Newsgroups: rec.audio,sci.electronics,sci.math Subject: Re: CD Format? Summary: This is not a Baud rate. Message-ID: <9160@drutx.ATT.COM> Date: 27 Oct 88 16:14:06 GMT Article-I.D.: drutx.9160 References: <3261@emory.uucp> <1185@ucsd.EDU> <2296@cadovax.UUCP> Organization: AT&T, Denver, CO Lines: 16 In article <2296@cadovax.UUCP>, keithd@cadovax.UUCP (Keith Doyle) writes: > > Lessee... If it's serial, it must be at least 44.1*16bits = 705.6 K baud To begin with, there are two channels, each delivering 16 bit samples at 44+ KHz. In addition, your use of the term "baud" is not correct. The Baud rate is the rate of state transitions. This is the same as bps only if each state transition (shift in phase/frequency/amplitude) conveys only a single bit. If, for example, each state transition carries two bits (which would require four distinct state values), then the Baud rate is 1/2 the bps. > Keith Doyle > # {ucbvax,decvax}!trwrb!cadovax!keithd Contel Business Systems 213-323-8170 Tom Barber