Xref: utzoo rec.audio:8852 sci.electronics:4196
Path: utzoo!attcan!uunet!lll-winken!lll-tis!helios.ee.lbl.gov!nosc!ucsd!ucsbcsl!comdesign!ivucsb!todd
From: todd@ivucsb.UUCP (Todd Day)
Newsgroups: rec.audio,sci.electronics
Subject: Re: Extracting Mono from Stereo
Keywords: mono stereo signal processing
Message-ID: <361@ivucsb.UUCP>
Date: 31 Oct 88 15:33:21 GMT
References: <341@ivucsb.UUCP> <343@ivucsb.UUCP> <3836@ncrcae.Columbia.NCR.COM> <785@mplvax.nosc.MIL> <2125@iscuva.ISCS.COM> <357@ivucsb.UUCP> <4571@ptsfa.PacBell.COM>
Reply-To: todd@ivucsb.UUCP (Todd Day)
Organization: The Audio Club at UCSB, Isla Vista, California
Lines: 26

In article <4571@ptsfa.PacBell.COM> dmt@ptsfa.PacBell.COM (Dave Turner) writes:
_In article <357@ivucsb.UUCP> todd@ivucsb.UUCP (Todd Day) writes:
_>
_>Those 'vocals removers' typically subtract the right from the left channel
_>(or vice versa).  That gives us:
_>(L+M/2)-(R+M/2) = L + M/2 - R - M/2 = L - R
_>
_>Now, you want to subtract this from the original source (L+M+R):
_>(L+M+R) - (L-R) = L + M + R - L + R = M+2R
_>which is not what you intended...
_
_You stopped too soon. Now subtract R twice:
_
_	M+2R - 2R = M
_
_This seems too simple. What did I miss?

Where did you get just R?  By my definitions, you don't have R, but the
right channel has R+0.5M.  No matter what you do, it is ?impossible? to
manipulate M out of the system algebraically.


 
   /| Todd Day (805)968-9352 |\              "I go to school, but
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