Path: utzoo!attcan!uunet!husc6!uwvax!tank!ncar!gatech!mcnc!rti!sunpix!matthew
From: matthew@sunpix.UUCP ( Sun NCAA)
Newsgroups: comp.unix.questions
Subject: Re: Telling csh about multiple, machine-dependent libraries
Summary: solved...
Keywords: csh bin libraries
Message-ID: <277@greens.UUCP>
Date: 18 Nov 88 16:01:50 GMT
References: <173@heart-of-gold>
Organization: Sun Microsystems, Research Triangle Park, NC
Lines: 64

In article <173@heart-of-gold>, jc@heart-of-gold (John M Chambers) writes:
> Here's one that someone has gotta have solved already:
> 
> We have NFS-mounted filesystems on a lot of different kinds of machines,
> and of course there is a problem with trying to execute binary files on
> the wrong machine.  It's pretty easy to build the binaries, of course;
> I just set up a heirarchy:
> 	~foo/src	contains generic source.
> 	~foo/sun2	contains a Makefile and binaries for a Sun2
> 	~foo/sun3	contains a Makefile and binaries for a Sun3
> 	~foo/vax	contains a Makefile and binaries for a VAX
> 	~foo/x286	contains a Makefile and binaries for a 80286/Xenix
> 	~foo/x386	contains a Makefile and binaries for a 80386/Xenix 
> and so on.  Source files are linked from src as necessary.
> 
> Now, when I log in, I'd like  to include the right directory in my search
> path.  My latest (failed) attempt in cshrc looks like:
> 
> | set mtype = bin
> | if (`sun2`) set mtype = sun2
> | if (`sun3`) set mtype = sun3
> | if (`sun4`) set mtype = sun4
> | set path=(. ~/{$mtype,sh,csh,awk} /bin /usr/{ucb,etc,local,local/{$mtype,sh},bin,lib,dos,hosts,games,demo,NeWS/{bin,demo}} /etc)
> 

Close, but not quite right.  We have to do build for not just different
machines, but different OS also. 

What you need to do is use the `arch` command to differenciet(sp?) between
the different machine types. IE:

set mtype = `arch` 

is what you are looking for. We also use a shell script to determine the OS
level also. Here it is:

#! /bin/csh -f
# Prints "os3", "os4", or "os_unknown"
# Set rel_str to the string following "Release" in /vmunix

#/*note: following two line are actually one. broken here due to length > 80 */
set rel_str = `strings /vmunix | grep Release | 
awk '{ for (i=0; i<NF; i++) if ($i == "Release"){ i++; print $i; exit; } }'`

if ($rel_str:r == 3 || $rel_str == Sys4-3.2) then
  echo "os3"
else if ($rel_str:r == 4) then
  echo "os4"
else
  echo "os_unknown"
endif


This way we can create directories for 'sun3-os3', 'sun3-os4', 'sun4-os3',
and 'sun4-os4' with a simple:

set PATH = $PATH ~/`arch`-`os`


Hope this helps.
-- 
Matthew Lee Stier     (919) 469-8300|
Sun Microsystems ---  RTP, NC  27560|          "Wisconsin   Escapee"
uucp: {sun, rti}!sunpix!matthew     |