Path: utzoo!lsuc!hcr!paul
From: paul@hcr.UUCP (Paul Jackson)
Newsgroups: can.general
Subject: Re: SIN Number
Message-ID: <4367@hcr.UUCP>
Date: Wed, 21-Dec-88 10:24:27 EST
Article-I.D.: hcr.4367
References: <302@idacom.UUCP> <723@apss.apss.ab.ca> <1902@pembina.UUCP> <420@perle.UUCP>
Reply-To: paul@compiler.UUCP (Paul Jackson)
Distribution: can
Organization: HCR Corporation, Toronto
Lines: 17
Keywords: Checksum Procedure
Summary: 

In article <420@perle.UUCP> dave@perle.UUCP (David LeReverend) writes:
>... The last (ninth) digit is a "check sum", and it can be
>determined using the 9 simple steps shown below.
>Steps:
>1) Use the even digits to form a four-digit number.
>2) Double this four-digit number.
>3) Sum the digits of the number determined in step 2.
>4) Use the odd digits (but not "C") to form another four-digit number.
>5) Sum the digits of the number determined in step 4.
>6) Add the results from steps 3 and 5.
>7) From the result of step 6, determine the next highest multiple of 10.
>8) Find the difference between the results from steps 6 and 7.
>9) The result of step 8 becomes the last (ninth) digit in the SIN.
>David LeReverend
	This algorithm did NOT work for my SIN (my arithmetic is admittedly
up to the usual standards in this society, but dc wouldn't lie to me, would
it?)