Path: utzoo!attcan!uunet!lll-winken!lll-lcc!ames!mailrus!cwjcc!arun@dsrgsun.ces.cwru.edu From: arun@dsrgsun.ces.cwru.edu (Arun Lakhotia) Newsgroups: comp.lang.prolog Subject: Yet another perfect number program Keywords: perfect numbers, prime numbers Message-ID: <358@cwjcc.CWRU.Edu> Date: 22 Dec 88 05:54:55 GMT Sender: news@cwjcc.CWRU.Edu Reply-To: arun@dsrgsun.ces.cwru.edu (Arun Lakhotia) Organization: Case Western Reserve University Lines: 70 When the Cat is away the mice play. Now that RO'K is ... Following is a program for generating perfect numbers. It is different from others as it uses the theorem cited by Thomas Sj|land. > if (2^p-1) is a (mersenne) prime > then (2^p-1) * 2^(p-1) is a perfect number. NOTE: The isprime/1 algorithm is substantially different and faster than what I posted earlier. It is *NOT* derived from any previous version. The previous isprime algorithm checked for the existence of a divisor for N between 1 .. N//2+1. This algorithm checks for divisors between I .. N//I+1 starting from I = 1. The algorithm is substantially faster and gives the 6, 28, 496, 8128, and 33550336 perfect numbers in a wink. Numbers beyond that exceed the integer bounds of SICStus and Quintus Prologs. /* checking for primeness */ divides(Dividend,Divisor,Quotient) :- Quotient is Dividend//Divisor, Dividend is Quotient * Divisor. isprime(2). isprime(Number) :- \+ divides(Number, 2), isprime(Number, 1, Number). isprime(_M, Lower, Upper) :- Lower >= Upper,!. isprime(Number, Lower, _Upper) :- % Lower < _Upper, divides(Number, Lower, Quotient),!, Lower = 1, Lower1 is Lower +1, isprime(Number, Lower1, Quotient). isprime(Number, Lower, _Upper) :- % Lower < _Upper, Lower1 is Lower +1, Upper1 is Number//Lower+1, isprime(Number, Lower1, Upper1). /* Perfect Numbers */ perfect_numbers :- write('P. No'), tab(4), write('Merseme Prime = 2^p-1'),nl, perfect_number(PNo, Merseme/N), write(PNo), tab(3), write((Merseme = 2^N-1)), nl, fail. perfect_number(PNo, Merseme/N) :- candidate(PNo, Merseme/N), isprime(Merseme). % Is merseme prime candidate(PNo, M/N) :- int(N), N > 1, pow2(N, P), % P = 2^N M is P-1, N1 is N-1, pow2(N1, P1), % 2^(N-1) PNo is M * P1. % 2^N-1 * 2^(N-1) int(1). int(I) :- int(I1), I is I1+1. pow2(N, P) :- P is 1 << N. = Arun