Path: utzoo!utgpu!watmath!julian!uwovax!4203_5067
From: 4203_5067@uwovax.uwo.ca (Mike MS D.)
Newsgroups: can.general
Subject: Re: Re: SIN number
Message-ID: <1185@uwovax.uwo.ca>
Date: 4 Jan 89 10:34:19 GMT
References: <302@idacom.UUCP> <723@apss.apss.ab.ca> <1902@pembina.UUCP> <420@perle.UUCP> <4367@hcr.UUCP>
Lines: 18
Organisation: University of Western Ontario, Canada

In article <4367@hcr.UUCP>, paul@hcr.UUCP (Paul Jackson) writes:
> In article <420@perle.UUCP> dave@perle.UUCP (David LeReverend) writes:
>>... The last (ninth) digit is a "check sum", and it can be
>>determined using the 9 simple steps shown below.
>>Steps:
>>1) Use the even digits to form a four-digit number.
>>2) Double this four-digit number.
>>3) Sum the digits of the number determined in step 2.
>>4) Use the odd digits (but not "C") to form another four-digit number.
>>5) Sum the digits of the number determined in step 4.
>>6) Add the results from steps 3 and 5.
>>7) From the result of step 6, determine the next highest multiple of 10.
>>8) Find the difference between the results from steps 6 and 7.
>>9) The result of step 8 becomes the last (ninth) digit in the SIN.
>>David LeReverend
> 	This algorithm did NOT work for my SIN (my arithmetic is admittedly
> up to the usual standards in this society, but dc wouldn't lie to me, would
> it?)