Path: utzoo!attcan!uunet!husc6!mailrus!ames!pasteur!ucbvax!hplabs!hpfcdc!steve
From: steve@hpfcdc.HP.COM (Steve Taylor)
Newsgroups: comp.sys.hp
Subject: Re: HP9836 BASIC -- HELP !!
Message-ID: <5570098@hpfcdc.HP.COM>
Date: 3 Jan 89 19:21:08 GMT
References: <281@vmsa.technion.ac.il>
Organization: HP Ft. Collins, Co.
Lines: 30

Benjamin Cohen asks:
}  SUB Out_word(@GPIB,INTEGER Xbuf(*),N)
}       INTEGER Odata
}       FOR I=1 TO N
}         Odata=ROTATE(Xbuf(I),8)
}         OUTPUT @GPIB USING "#,W";Odata
}       NEXT I
}       SUBEND
}  This obviously is sending data to a GPIB device, but what would be the
}  equivalent in C?  What does the ROTATE function do?

It appears the program is sending data to a device which expects low-byte,
high-byte, rather than high-byte, low-byte.  Since ROTATE works on 16-bit
quantities, the value of 8 means swap bytes.

}  What does the
}  output look like (binary word transfer or formatted ASCII)?

As Sid Cowles says:  i'd guess that the io-path, @gpib, was assigned with
}  format off since the output statement is using a 2 byte word ("W") format
}  with no end-of-line sequence.

The "#" says no eol.  The swap above also implies binary data.  To be sure,
look for the statement ASSIGN @Gpib TO ... in the calling portion of the
program.  FORMAT OFF is the default for devices.  If it were formatted ASCII
then the ASSIGN statement would include a FORMAT ON clause.

I'm not familiar with DIL, so perhaps someone who is will give you the C
equivalent.
						Regards, Steve Taylor