Path: utzoo!attcan!uunet!lll-winken!lll-lcc!ames!hc!pprg.unm.edu!unmvax!gatech!emory!arnold
From: arnold@emory.uucp (Arnold D. Robbins {EUCC})
Newsgroups: comp.unix.questions
Subject: Re: "yesterdate" function?
Message-ID: <3562@emory.uucp>
Date: 4 Jan 89 17:40:13 GMT
References: <19100001@hpficad.HP.COM>
Reply-To: arnold@emory.UUCP (Arnold D. Robbins {EUCC})
Organization: Emory University
Lines: 29

In article <19100001@hpficad.HP.COM> mcr@hpficad.HP.COM (Matt Reprogle) writes:
>I need a way to get yesterday's date in YYMMDD format in a Unix script and put
>it in a file.   I don't want to write a C program implementing an entire
>calendar to do it. 
>
>Can anyone help?  

This is too hard to pass up.

	#include <time.h>
	#define ONEDAY	(24 * 60 * 60)	/* seconds in a day */

	main ()
	{
		long yesterday;
		struct tm* then;

		(void) time (& yesterday);
		yesterday -= ONEDAY;
		then = localtime (& yesterday);
		(void) printf ("%d%02d%02d\n", then->tm_year,
			then->tm_mon, then->tm_mday);
		return 0;
	}
-- 
"Unix is a Registered  | Arnold Robbins -- Emory University Computing Center
Bell of AT&T Trademark | DOMAIN: arnold@unix.cc.emory.edu		
Laboratories."         | UUCP: gatech!emory!arnold	PHONE:	+1 404 727-7636
        -- Donn Seeley | BITNET: arnold@emoryu1		FAX:	+1 404 727-2599